DeepSeek V4.1 Flash (Venice) (thinking on) on Choose the value-maximising project portfolio under a budget, an hours cap, prerequisites and exclusions
DDeepSeek V4.1 Flash (Venice)thinking on · venice-mini-agent v1.3.1 · cloud · 2026-10-28 · by @bobsiopener
- Estimated cost
- $0.0030
- Wall time
- 9s
- Human step-ins
- 0
- Outcome
- Pass
Compare with other models on this task →
Summary
Exact prompt
# Choose next quarter's project portfolio Inputs: `projects.csv` (cost, engineering hours and estimated value of each candidate project, plus prerequisites) and `constraints.json` (budget, available hours, pairs that can't both be funded). Pick the set of projects that maximises total value. - Total cost must not exceed the budget, and total hours must not exceed the available hours. - A project can only be funded if all its prerequisites are funded too. - At most one project of each mutually exclusive pair may be funded. - Then answer one what-if: if the budget were cut by 10% (hours unchanged), what is the best total value achievable? Write `out/portfolio.json`: `{"selected": [<project ids, sorted>], "total_value": <n>, "total_cost": <n>, "total_hours": <n>, "value_if_budget_cut_10pct": <n>}`. ## How this run works - Work on your own: nobody will answer questions in this task, and writing to `ask/` counts against the run. - Write only under `out/`. Create `out/` if it is missing. Inputs are synthetic; don't fetch anything from the network. - Scoring is partial credit: each listed check is pass/fail, and the score is the share passed. Numbers are compared to within 0.005 unless the task says otherwise.
Pick the best set of 15-17 candidate projects under two competing limits (money and engineering hours), with prerequisite chains and mutually exclusive pairs, then answer a budget-cut what-if. The data is drawn so that ranking by value-for-money is strictly worse than the optimum and ignoring the hours cap gives a different set. The hidden key is the unique exact optimum. Original benchmark task written for usecaserank.com (not based on a specific public post). Headless, offline run on a reproducible fixture. Cost shown is a list-price estimate (measured tokens x the site's price table).
Success criteria: optimal_selection optimal_value cost_and_hours what_if_budget_cut
Setup notes: Batch 18 case t01-portfolio-under-budget (offline, synthetic inputs, seed 110553857). Autonomous case: no stand-in user and the agent never needs to check with the user; any file the solver wrote to ask/ is counted as a measured intervention (0) and blocks a pass. Prompt = TASK.md verbatim. Hidden key kept outside the solver's work dir. Scored on the box with the case's scorer; pass = every check true and no ask/ files. Tools: list_files/read_file/write_file/run_shell (venice-mini-agent v1.3), web disabled. Single run, no retries. 1-min load average at scoring 1.62 (8 cores). Time-zone results depend on the system time-zone database: tzdata 2026c-0+deb13u1 (Python zoneinfo). Harness: venice-mini-agent v1.3.1 via the Venice OpenAI-compatible API: same tool loop, system prompt and limits as the cases 02-25 Venice runs (max 25 turns, max 16,000 output tokens per call, temperature 0.2, Venice system prompt and web search off, per-run cost cap $0.05, thinking on (model default)). Same task text, work-dir layout and scorer as the Claude runs of this case. Cost = measured per-call tokens x Venice list price; paid from the Venice DIEM daily allowance. Harness: venice-mini-agent v1.3.1 via Venice OpenAI-compatible API (max 16,000 output tokens per call, $0.05 run cap). Score: 4/4. Cost is an ESTIMATE: measured per-call tokens x Venice list price (paid from Venice DIEM allowance; Venice billing not itemized). input_tokens include cached reads. Single run.
Estimated cost List-price estimate; not actually billed.
Metrics
- Estimated cost
- $0.0030
- Wall time
- 9s
- Human step-ins
- 0
- Turns
- 4
| Model | Input tok | Output tok | Cost |
|---|---|---|---|
| DDeepSeek V4.1 Flash (Venice)venice/deepseek-v4-1-flashthinking on | 6,059 | 1,196 | $0.0030 |
Reproduce this run
- Use the use case prompt on the use case page.
- Same setup: DeepSeek V4.1 Flash (Venice) (venice/deepseek-v4-1-flash, thinking on) via
venice-mini-agent v1.3.1, cloud. - It counts as a success only if it meets every success criterion: optimal_selection optimal_value cost_and_hours what_if_budget_cut
- Log model, tokens, wall time, human step-ins and the evidence log, then submit it as a reproduction. A different model? Submit a head-to-head rerun.
How runs are scored: Methodology.
Was this useful?
Automated checks
Trust 80% comes from these checks (how Trust % works).
- Run date is not in the future : passed
- Model is in the dated pricing table : passed
- Cost recomputed from tokens matches : passed
- Cached tokens are consistent : passed
- Output throughput is plausible : passed
- Autonomy matches step-ins : passed
- Step-ins do not exceed turns : passed
- Retries agree with first-try result : passed
- Evidence log SHA-256 matches : passed
- Evidence log is substantial : passed
Evidence log
[
{
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"venice_output": {
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"harness_version": "1.3.1",
"max_tokens_per_call": 16000,
"disable_thinking": false,
"run_cost_cap": 0.05,
"no_tools": false,
"resumed_from": null,
"model": "deepseek-v4-1-flash",
"start": "2026-10-27T20:17:26-0400",
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"cost_usd_venice_list": 0.003034,
"billed_reported_by_venice": 0.003034,
"wall_seconds": 8.9,
"final_message": "Solved via exhaustive search over all 2^15 subsets (with prerequisite, exclusivity, budget and hours checks).\n\n**Result** \u2014 optimal portfolio:\n- Selected: PRJ-A, PRJ-C, PRJ-G, PRJ-H, PRJ-K, PRJ-N\n- Total value: 1000k, cost: 540k (\u2264 648k budget), hours: 2227 (exactly the available limit)\n- Prerequisites satisfied (PRJ-N\u2192PRJ-H), exclusivity respected (only G of F/G, only N of J/N)\n- Budget cut 10% \u2192 583.2k: the same portfolio still fits (540k), so best value remains 1000k\n\nWrote `out/portfolio.json` with the required fields.",
"error": null,
"fatal": false
},
"trace": [
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"turn": 1,
"response": {
"id": "chatcmpl-a62fcce1",
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"message": {
"content": "I'll start by inspecting the input files.",
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{
"turn": 1,
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"result": "./TASK.md\n./constraints.json\n./projects.csv"
},
{
"turn": 1,
"tool": "read_file",
"args": {
"path": "projects.csv"
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"result": "project_id,cost_k_usd,eng_hours,est_value_k_usd,prerequisites\nPRJ-A,70,441,162,\nPRJ-B,98,629,93,\nPRJ-C,69,252,159,\nPRJ-D,131,724,207,PRJ-C\nPRJ-E,21,702,33,PRJ-C\nPRJ-F,62,468,49,\nPRJ-G,102,542,182,\nPRJ-H,47,505,117,\nPRJ-I,157,519,379,PRJ-E\nPRJ-J,49,303,82,\nPRJ-K,94,342,125,\nPRJ-L,150,601,110,\nPRJ-M,87,442,152,\nPRJ-N,158,145,255,PRJ-H\nPRJ-O,28,689,85,\n"
},
{
"turn": 1,
"tool": "read_file",
"args": {
"path": "constraints.json"
},
"result": "{\n \"budget_k_usd\": 648,\n \"eng_hours_available\": 2227,\n \"mutually_exclusive\": [\n [\n \"PRJ-F\",\n \"PRJ-G\"\n ],\n [\n \"PRJ-J\",\n \"PRJ-N\"\n ]\n ]\n}"
},
{
"turn": 2,
"response": {
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"type": "function",
"function": {
"name": "run_shell",
"arguments": "{\"command\":\"cat > /tmp/solve.py << 'EOF'\\nimport csv, json, itertools\\n\\nprojs = {}\\nwith open('projects.csv') as f:\\n for r in csv.DictReader(f):\\n projs[r['project_id']] = {\\n 'cost': int(r['cost_k_usd']),\\n 'hours': int(r['eng_hours']),\\n 'value': int(r['est_value_k_usd']),\\n 'pre': [p for p in r['prerequisites'].split(';') if p],\\n }\\n\\ncons = json.load(open('constraints.json'))\\nbudget = cons['budget_k_usd']\\nhours = cons['eng_hours_available']\\nme = [tuple(p) for p in cons['mutually_exclusive']]\\n\\nids = sorted(projs)\\nn = len(ids)\\n\\ndef solve(budget):\\n best = None\\n for mask in range(1 << n):\\n sel = [ids[i] for i in range(n) if mask >> i & 1]\\n s = set(sel)\\n ok = True\\n for p in sel:\\n for pre in projs[p]['pre']:\\n if pre not in s:\\n ok = False; break\\n if not ok: break\\n if not ok: continue\\n for a, b in me:\\n if a in s and b in s:\\n ok = False; break\\n if not ok: continue\\n c = sum(projs[p]['cost'] for p in sel)\\n h = sum(projs[p]['hours'] for p in sel)\\n if c > budget or h > hours: continue\\n v = sum(projs[p]['value'] for p in sel)\\n if best is None or v > best[0]:\\n best = (v, c, h, sel)\\n return best\\n\\nv, c, h, sel = solve(budget)\\nprint('best', v, c, h, sorted(sel))\\nv2, c2, h2, sel2 = solve(int(budget * 0.9))\\nprint('cut', v2, c2, h2, sorted(sel2))\\n\\nout = {\\n \\\"selected\\\": sorted(sel),\\n \\\"total_value\\\": v,\\n \\\"total_cost\\\": c,\\n \\\"total_hours\\\": h,\\n \\\"value_if_budget_cut_10pct\\\": v2,\\n}\\nimport os\\nos.makedirs('out', exist_ok=True)\\njson.dump(out, open('out/portfolio.json', 'w'), indent=1)\\nprint(out)\\nEOF\\npython3 /tmp/solve.py\"}"
}
}
],
"role": "assistant",
"reasoning_content": "Let me solve this with a brute-force / ILP approach. 15 projects, 2^15 = 32768, easy brute force.\n\nLet me write a script."
},
"finish_reason": "tool_calls",
"logprobs": null,
"raw_output": null
}
],
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"venice_parameters": {
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"enable_e2ee": true,
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},
{
"turn": 2,
"tool": "run_shell",
"args": {
"command": "cat > /tmp/solve.py << 'EOF'\nimport csv, json, itertools\n\nprojs = {}\nwith open('projects.csv') as f:\n for r in csv.DictReader(f):\n projs[r['project_id']] = {\n 'cost': int(r['cost_k_usd']),\n 'hours': int(r['eng_hours']),\n 'value': int(r['est_value_k_usd']),\n 'pre': [p for p in r['prerequisites'].split(';') if p],\n }\n\ncons = json.load(open('constraints.json'))\nbudget = cons['budget_k_usd']\nhours = cons['eng_hours_available']\nme = [tuple(p) for p in cons['mutually_exclusive']]\n\nids = sorted(projs)\nn = len(ids)\n\ndef solve(budget):\n best = None\n for mask in range(1 << n):\n sel = [ids[i] for i in range(n) if mask >> i & 1]\n s = set(sel)\n ok = True\n for p in sel:\n for pre in projs[p]['pre']:\n if pre not in s:\n ok = False; break\n if not ok: break\n if not ok: continue\n for a, b in me:\n if a in s and b in s:\n ok = False; break\n if not ok: continue\n c = sum(projs[p]['cost'] for p in sel)\n h = sum(projs[p]['hours'] for p in sel)\n if c > budget or h > hours: continue\n v = sum(projs[p]['value'] for p in sel)\n if best is None or v > best[0]:\n best = (v, c, h, sel)\n return best\n\nv, c, h, sel = solve(budget)\nprint('best', v, c, h, sorted(sel))\nv2, c2, h2, sel2 = solve(int(budget * 0.9))\nprint('cut', v2, c2, h2, sorted(sel2))\n\nout = {\n \"selected\": sorted(sel),\n \"total_value\": v,\n \"total_cost\": c,\n \"total_hours\": h,\n \"value_if_budget_cut_10pct\": v2,\n}\nimport os\nos.makedirs('out', exist_ok=True)\njson.dump(out, open('out/portfolio.json', 'w'), indent=1)\nprint(out)\nEOF\npython3 /tmp/solve.py"
},
"result": "exit=0\nstdout:\nbest [REDACTED:phone] ['PRJ-A', 'PRJ-C', 'PRJ-G', 'PRJ-H', 'PRJ-K', 'PRJ-N']\ncut [REDACTED:phone] ['PRJ-A', 'PRJ-C', 'PRJ-G', 'PRJ-H', 'PRJ-K', 'PRJ-N']\n{'selected': ['PRJ-A', 'PRJ-C', 'PRJ-G', 'PRJ-H', 'PRJ-K', 'PRJ-N'], 'total_value': 1000, 'total_cost': 540, 'total_hours': 2227, 'value_if_budget_cut_10pct': 1000}\n\nstderr:\n"
},
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}
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"role": "assistant",
"reasoning_content": "The best solution uses cost 540, which is under 583.2 (10% cut of 648 = 583.2). So the answer is the same. Let me verify the budget cut: 648*0.9 = 583.2. Cost 540 <= 583.2, so same solution. Good.\n\nLet me double check the brute force is correct and there's no tie issue. Value 1000. Let me verify hours exactly 2227 = available. Good.\n\nLet me confirm the output file."
},
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},
{
"turn": 3,
"tool": "read_file",
"args": {
"path": "out/portfolio.json"
},
"result": "{\n \"selected\": [\n \"PRJ-A\",\n \"PRJ-C\",\n \"PRJ-G\",\n \"PRJ-H\",\n \"PRJ-K\",\n \"PRJ-N\"\n ],\n \"total_value\": 1000,\n \"total_cost\": 540,\n \"total_hours\": 2227,\n \"value_if_budget_cut_10pct\": 1000\n}"
},
{
"turn": 4,
"response": {
"id": "chatcmpl-dbedfb49",
"choices": [
{
"index": 0,
"message": {
"content": "Solved via exhaustive search over all 2^15 subsets (with prerequisite, exclusivity, budget and hours checks).\n\n**Result** \u2014 optimal portfolio:\n- Selected: PRJ-A, PRJ-C, PRJ-G, PRJ-H, PRJ-K, PRJ-N\n- Total value: 1000k, cost: 540k (\u2264 648k budget), hours: 2227 (exactly the available limit)\n- Prerequisites satisfied (PRJ-N\u2192PRJ-H), exclusivity respected (only G of F/G, only N of J/N)\n- Budget cut 10% \u2192 583.2k: the same portfolio still fits (540k), so best value remains 1000k\n\nWrote `out/portfolio.json` with the required fields.",
"role": "assistant",
"reasoning_content": "Let me verify the 10% cut: 648*0.9 = 583.2. The best solution costs 540 \u2264 583.2, so value stays 1000. Good.\n\nLet me double check the optimum by brute force \u2014 done exhaustively over 2^15. Good.\n\nVerify prerequisites: PRJ-N requires PRJ-H (included). PRJ-C no prereq. PRJ-G no prereq. PRJ-A none. PRJ-K none. Good. Mutually exclusive: F/G \u2014 only G. J/N \u2014 only N. Good.\n\nHours exactly 2227 = available. Cost 540 \u2264 648. Value 1000.\n\nDone."
},
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