Claude Opus 5.5 (effort default (no --effort flag) · thinking on) on Turn a minute-by-minute common-free-time scan into a sweep that handles 3,000 calendars in <3 s with identical output

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  "result": "I rewrote `common_free` in `slots.py`. The benchmark case (3,000 people \u00d7 60 intervals over 50,000,000 minutes) now runs in about **0.16 s**, well under the 3 s limit. On 20,000 random small inputs, its output matched the original exactly every time.\n\n**How it works:** instead of checking every minute, it does this:\n1. Drops empty intervals (`s >= e`) and ones entirely outside `[start, end)`, and trims the rest to the window.\n2. Sorts what's left and walks through it once. Any gap before the next busy interval of at least `min_len` minutes is a free slot. Touching or overlapping intervals merge, so the slots returned are the longest possible and in sorted order.\n3. Adds the final gap up to `end` under the same rule.\n\nThe total cost is one sort of all the busy intervals, so the window length no longer matters.\n\n**What the random tests covered:** touching, overlapping and empty intervals; intervals outside the window; `start == end` and `start > end`; and `min_len` values from \u22122 to 8. A `min_len` of zero or less still never produces zero-length slots, the same as the original.\n\nOne limit: the new version assumes integer times, as the module docstring says. With non-integer `start` or interval endpoints, the original would round results to its minute steps and the new version wouldn't, so they could differ. I didn't test that case.",
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